1) Introduction: From Derivatives to Integrals š
So far, weāve mastered derivativesātools that tell us how functions change at any instant. But what if we want to go backward? What if we have the rate of change (the derivative) and need to find the original function? Thatās where integration comes in! Integration is like the reverse of differentiation, and itās one of the most powerful ideas in calculus.
In this topic, weāll explore:
- Antiderivatives: The building blocks of integrationāwhat they are and how to find them.
- Geometric Meaning: How antiderivatives connect to the idea of "undoing" slopes.
- Why It Matters: Integration isnāt just mathāitās a key to solving real-world problems like finding areas, volumes, and total change.
Quick Recap: If \( f(x) \) is a function, its derivative \( f'(x) \) tells us the slope of the tangent line at any point. Integration asks: Given \( f'(x) \), whatās \( f(x) \)?
2) What Are Antiderivatives? The Reverse of Differentiation š
Imagine youāre given a speedometer reading (rate of change of distance). Can you figure out the total distance traveled? Thatās the idea behind an antiderivative. Itās a function that, when differentiated, gives you back the original function. š
Definition 8.1: Antiderivative
A function \( F(x) \) is an antiderivative of \( f(x) \) if:
\( F'(x) = f(x) \)
In simpler terms, if you take the derivative of \( F(x) \), you get \( f(x) \). For example, if \( f(x) = 2x \), then \( F(x) = x^2 \) is an antiderivative because \( \frac{d}{dx}(x^2) = 2x \).
But hereās the twist: thereās not just one antiderivative! If \( F(x) \) works, so does \( F(x) + C \) where \( C \) is any constant. Why? Because the derivative of a constant is zero: \( \frac{d}{dx}(C) = 0 \). So, for \( f(x) = 2x \), antiderivatives include \( x^2 \), \( x^2 + 5 \), \( x^2 - 3 \), etc. š
Example 1: Finding Basic Antiderivatives
Find an antiderivative of \( f(x) = 3x^2 \).
We need \( F(x) \) such that \( F'(x) = 3x^2 \). Think: What function, when differentiated, gives \( 3x^2 \)?
- Try \( F(x) = x^3 \). Then \( F'(x) = 3x^2 \), which matches!
- But \( F(x) = x^3 + 7 \) also works, since \( \frac{d}{dx}(x^3 + 7) = 3x^2 + 0 = 3x^2 \).
So, an antiderivative is \( F(x) = x^3 + C \), where \( C \) is any constant.
Example 2: Constant Functions
Find an antiderivative of \( f(x) = 4 \).
What function gives a derivative of 4?
- Try \( F(x) = 4x \). Then \( F'(x) = 4 \), which works!
- Add a constant: \( F(x) = 4x + C \), and \( F'(x) = 4 \) still holds.
Answer: \( F(x) = 4x + C \).
3) The General Antiderivative and Notation š
Since adding any constant to an antiderivative still works, we call the general antiderivative the set of all possible antiderivatives. This is written using the integral symbol \( \int \).
Definition 8.2: General Antiderivative (Indefinite Integral)
The general antiderivative of \( f(x) \), also called the indefinite integral, is:
\( \int f(x) \, dx = F(x) + C \)
where \( F'(x) = f(x) \), and \( C \) is the constant of integration.
The \( dx \) tells us the variable of integration (here, \( x \)). Think of \( \int \) as "undoing" the derivative.
Example 3: Using Integral Notation
Find \( \int 6x \, dx \).
We need \( F(x) \) such that \( F'(x) = 6x \).
- Try \( F(x) = 3x^2 \). Then \( F'(x) = 6x \), which fits.
- Include the constant: \( F(x) = 3x^2 + C \).
So, \( \int 6x \, dx = 3x^2 + C \).
Example 4: A Trickier One
Find \( \int \cos(x) \, dx \).
What functionās derivative is \( \cos(x) \)?
- Try \( F(x) = \sin(x) \). Then \( F'(x) = \cos(x) \), perfect!
- General form: \( F(x) = \sin(x) + C \).
Answer: \( \int \cos(x) \, dx = \sin(x) + C \).
4) Geometric Meaning: Antiderivatives and Slope Fields šŗļø
Antiderivatives arenāt just algebraicāthey have a geometric side! If \( f(x) \) is the slope of a curve at each point, the antiderivative \( F(x) \) is the curve itself. Imagine \( f(x) \) as a "slope field"āa map of tangent slopes. The antiderivative traces a path through that field.
For example, if \( f(x) = 2x \), the slopes get steeper as \( x \) increases. The antiderivative \( F(x) = x^2 + C \) is a family of parabolas, each shifted by \( C \), matching those slopes at every point.
Visualization Tip: Use Desmos to plot \( f(x) \) (e.g., \( 2x \)) and its antiderivative \( F(x) \) (e.g., \( x^2 + C \)). Adjust \( C \) to see the family of curves! š
Example 5: Geometric Interpretation
For \( f(x) = 2 \), what does \( \int 2 \, dx = 2x + C \) mean geometrically?
\( f(x) = 2 \) means the slope is 2 everywhereāa constant steepness. The antiderivative \( F(x) = 2x + C \) is a family of straight lines (e.g., \( y = 2x \), \( y = 2x + 1 \)), all with slope 2 but different y-intercepts based on \( C \).
5) Examples: Finding Antiderivatives Step-by-Step š
Example 6: Polynomial
Find \( \int (4x^3 - 2x + 1) \, dx \).
Work term by term:
- For \( 4x^3 \): Antiderivative is \( \frac{4x^4}{4} = x^4 \) (since \( \frac{d}{dx}(x^4) = 4x^3 \)).
- For \( -2x \): Antiderivative is \( \frac{-2x^2}{2} = -x^2 \).
- For \( 1 \): Antiderivative is \( x \).
- Add \( C \): \( x^4 - x^2 + x + C \).
Answer: \( \int (4x^3 - 2x + 1) \, dx = x^4 - x^2 + x + C \).
Example 7: Trigonometric
Find \( \int (\sin(x) + 2\cos(x)) \, dx \).
- For \( \sin(x) \): Antiderivative is \( -\cos(x) \) (since \( \frac{d}{dx}(-\cos(x)) = \sin(x) \)).
- For \( 2\cos(x) \): Antiderivative is \( 2\sin(x) \).
- Combine: \( -\cos(x) + 2\sin(x) + C \).
Answer: \( \int (\sin(x) + 2\cos(x)) \, dx = -\cos(x) + 2\sin(x) + C \).
6) Practice Questions šÆ
Fundamental Practice Questions š±
Instructions: Find the general antiderivative (indefinite integral) for each function. š
\( \int 5 \, dx \)
\( \int 3x \, dx \)
\( \int x^2 \, dx \)
\( \int 4x^3 \, dx \)
\( \int (2x + 3) \, dx \)
\( \int (x^2 - x) \, dx \)
\( \int \sin(x) \, dx \)
\( \int \cos(x) \, dx \)
\( \int (3x^2 + 2x - 1) \, dx \)
\( \int (4\sin(x) - \cos(x)) \, dx \)
Challenging Practice Questions š
Instructions: These require deeper understanding or interpretation. š§
Find \( \int (x^3 + 2x^2 - x + 5) \, dx \) and verify by differentiating your answer.
If \( F(x) = \int (2x - 3) \, dx \), find \( F(2) - F(1) \) for a specific \( C \) (e.g., \( C = 0 \)). What does this represent geometrically?
Explain why \( \int 0 \, dx = C \). What does this mean about the family of antiderivatives?
Given \( f(x) = x^2 \), find two different antiderivatives and plot them using Desmos. How do they differ?
Suppose a carās velocity is \( v(t) = 3t^2 \) (in meters/second). Find the position function \( s(t) = \int v(t) \, dt \) with initial position \( s(0) = 10 \).
7) Summary & Cheat Sheet š
7.1) Antiderivatives
\( F(x) \) is an antiderivative of \( f(x) \) if \( F'(x) = f(x) \). General form: \( \int f(x) \, dx = F(x) + C \).
7.2) Geometric Meaning
\( f(x) \) gives slopes; \( F(x) \) is the curve with those slopes. \( C \) shifts the curve vertically.
7.3) Basic Rules
- \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \) (if \( n \neq -1 \))
- \( \int \sin(x) \, dx = -\cos(x) + C \)
- \( \int \cos(x) \, dx = \sin(x) + C \)
Youāve just unlocked the door to integration! Next, weāll dive into rules to make finding antiderivatives even easier. š