📐 Level 1 - Topic 5: Trigonometric Ratios in Right Triangles 📐

1) Right Triangles - The Foundation 📐

Trigonometry is deeply connected to triangles, especially right triangles. A right triangle is a triangle with one angle that is exactly \( 90^\circ \) (a right angle).

A Right Triangle is a triangle with one angle measuring exactly \( 90^\circ \). The side opposite the right angle is called the hypotenuse, and the other two sides are called legs.

Key Parts of a Right Triangle:

  • Right Angle: The \( 90^\circ \) angle, often marked with a small square.
  • Hypotenuse: The side opposite the right angle. It's always the longest side of the right triangle.
  • Legs: The two sides that form the right angle. When we consider an acute angle (less than \( 90^\circ \)) within the right triangle, we refer to the legs as:
    • Opposite Side: The leg directly across from the angle we are considering.
    • Adjacent Side: The leg next to the angle we are considering (that is not the hypotenuse).

Consider a right triangle \( \triangle ABC \) where \( \angle C = 90^\circ \). Side \( AB \) is the hypotenuse. If we consider angle \( \angle A \), then side \( BC \) is the opposite side and side \( AC \) is the adjacent side. If we consider angle \( \angle B \), then side \( AC \) is the opposite side and side \( BC \) is the adjacent side.


2) The Six Trigonometric Ratios - Sine, Cosine, Tangent, and Their Reciprocals 🔄

For a right triangle, we define six fundamental trigonometric ratios based on the ratios of the lengths of its sides relative to an acute angle \( \theta \) (let's assume \( \theta \) is one of the non-right angles in the triangle). The three primary ratios are sine, cosine, and tangent.

Let \( \theta \) be an acute angle in a right triangle. Define the trigonometric ratios as follows:

  • Sine of \( \theta \) (sin \( \theta \)): Ratio of the length of the opposite side to the length of the hypotenuse.

    \( \sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}} \)

  • Cosine of \( \theta \) (cos \( \theta \)): Ratio of the length of the adjacent side to the length of the hypotenuse.

    \( \cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}} \)

  • Tangent of \( \theta \) (tan \( \theta \)): Ratio of the length of the opposite side to the length of the adjacent side.

    \( \tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}} \)

Mnemonic: SOH CAH TOA

A helpful mnemonic to remember these ratios is SOH CAH TOA:

  • SOH: Sine = Opposite / Hypotenuse
  • CAH: Cosine = Adjacent / Hypotenuse
  • TOA: Tangent = Opposite / Adjacent
Say "SOH CAH TOA" to yourself a few times to help memorize these!

Reciprocal Trigonometric Ratios: Cosecant, Secant, Cotangent

There are also three reciprocal trigonometric ratios, which are simply the reciprocals of sine, cosine, and tangent:

  • Cosecant of \( \theta \) (csc \( \theta \)): Reciprocal of sine.

    \( \csc(\theta) = \frac{1}{\sin(\theta)} = \frac{\text{Hypotenuse}}{\text{Opposite}} \)

  • Secant of \( \theta \) (sec \( \theta \)): Reciprocal of cosine.

    \( \sec(\theta) = \frac{1}{\cos(\theta)} = \frac{\text{Hypotenuse}}{\text{Adjacent}} \)

  • Cotangent of \( \theta \) (cot \( \theta \)): Reciprocal of tangent.

    \( \cot(\theta) = \frac{1}{\tan(\theta)} = \frac{\text{Adjacent}}{\text{Opposite}} \)

Note: These trigonometric ratios are *dependent only on the angle* \( \theta \), not on the size of the right triangle itself. As long as the angle \( \theta \) is the same, the ratios of sides will be constant for all similar right triangles.


3) Finding Trigonometric Ratios - Examples 🎯

Example 1: Finding Trigonometric Ratios Given Side Lengths

Consider a right triangle with legs of length 3 and 4, and hypotenuse of length 5. Let \( \theta \) be the angle opposite the side of length 3. Find \( \sin(\theta), \cos(\theta), \tan(\theta) \).

Solution:

  • Opposite side = 3, Adjacent side = 4, Hypotenuse = 5
  • \( \sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{3}{5} \)
  • \( \cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}} = \frac{4}{5} \)
  • \( \tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{3}{4} \)

Example 2: Using Trigonometric Ratios to Find Unknown Side

In a right triangle, one acute angle is \( 30^\circ \) and the hypotenuse is 10 cm. Find the length of the side opposite the \( 30^\circ \) angle.

Solution:

  • Let \( x \) be the length of the opposite side.
  • We know \( \sin(30^\circ) = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{x}{10} \).
  • We know \( \sin(30^\circ) = \frac{1}{2} \) (we'll learn common trigonometric values later, but for now, assume you know this or can use a calculator).
  • So, \( \frac{1}{2} = \frac{x}{10} \). Solving for \( x \), we get \( x = 10 \times \frac{1}{2} = 5 \) cm.
  • The side opposite the \( 30^\circ \) angle is 5 cm.

Important: Make sure you correctly identify the opposite, adjacent, and hypotenuse sides *relative to the angle* you are working with in the right triangle!


4) Trigonometric Ratios for Special Angles: \( 30^\circ \), \( 45^\circ \), \( 60^\circ \) 🌟

Certain angles appear very frequently in trigonometry and geometry, and it's essential to know their trigonometric ratios exactly (without relying on calculators). These are \( 30^\circ \), \( 45^\circ \), and \( 60^\circ \) (or \( \frac{\pi}{6}, \frac{\pi}{4}, \frac{\pi}{3} \) radians).

Trigonometric Ratios for \( 30^\circ \) and \( 60^\circ \) (using a 30-60-90 triangle):

Consider a 30-60-90 right triangle. The ratios of its sides are \( 1 : \sqrt{3} : 2 \) (opposite to \( 30^\circ \) : opposite to \( 60^\circ \) : hypotenuse). Using these ratios:

  • \( \sin(30^\circ) = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{1}{2} \)
  • \( \cos(30^\circ) = \frac{\text{Adjacent}}{\text{Hypotenuse}} = \frac{\sqrt{3}}{2} \)
  • \( \tan(30^\circ) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{1}{\sqrt{3}} = \frac{\sqrt{3}}{3} \) (rationalized)
  • \( \sin(60^\circ) = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{\sqrt{3}}{2} \)
  • \( \cos(60^\circ) = \frac{\text{Adjacent}}{\text{Hypotenuse}} = \frac{1}{2} \)
  • \( \tan(60^\circ) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{\sqrt{3}}{1} = \sqrt{3} \)

Trigonometric Ratios for \( 45^\circ \) (using a 45-45-90 triangle):

Consider a 45-45-90 right triangle (isosceles right triangle). The ratios of its sides are \( 1 : 1 : \sqrt{2} \) (legs : hypotenuse). Using these ratios:

  • \( \sin(45^\circ) = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2} \) (rationalized)
  • \( \cos(45^\circ) = \frac{\text{Adjacent}}{\text{Hypotenuse}} = \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2} \) (rationalized)
  • \( \tan(45^\circ) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{1}{1} = 1 \)

Summary Table of Trigonometric Ratios for Special Angles:

Angle \( \theta \) \( \sin(\theta) \) \( \cos(\theta) \) \( \tan(\theta) \)
\( 30^\circ = \frac{\pi}{6} \) rad \( \frac{1}{2} \) \( \frac{\sqrt{3}}{2} \) \( \frac{\sqrt{3}}{3} \)
\( 45^\circ = \frac{\pi}{4} \) rad \( \frac{\sqrt{2}}{2} \) \( \frac{\sqrt{2}}{2} \) \( 1 \)
\( 60^\circ = \frac{\pi}{3} \) rad \( \frac{\sqrt{3}}{2} \) \( \frac{1}{2} \) \( \sqrt{3} \)

Memorize these exact values! They are fundamental and will save you time in problem-solving and build a deeper understanding of trigonometry. Practice recalling these values without a calculator.


5) Practice Questions 🎯

5.1 Fundamental – Applying Ratios

1. Define sine, cosine, and tangent ratios for an acute angle in a right triangle using opposite, adjacent, and hypotenuse sides.

2. What is the mnemonic SOH CAH TOA and how does it help remember the trigonometric ratios?

3. In a right triangle, if the opposite side is 6 and the hypotenuse is 10, what is the sine of the angle?

4. In a right triangle, if the adjacent side is 8 and the hypotenuse is 17, what is the cosine of the angle?

5. In a right triangle, if the opposite side is 5 and the adjacent side is 12, what is the tangent of the angle?

6. What are the exact values of \( \sin(30^\circ) \), \( \cos(30^\circ) \), and \( \tan(30^\circ) \)?

7. What are the exact values of \( \sin(45^\circ) \), \( \cos(45^\circ) \), and \( \tan(45^\circ) \)?

8. What are the exact values of \( \sin(60^\circ) \), \( \cos(60^\circ) \), and \( \tan(60^\circ) \)?

9. If \( \sin(\theta) = \frac{3}{5} \) in a right triangle, and the hypotenuse is 20, what is the length of the opposite side?

10. If \( \tan(\theta) = \frac{4}{3} \) in a right triangle, and the adjacent side is 9, what is the length of the opposite side?

5.2 Challenging – Problem Solving & Deeper Thinking 💪🚀

1. In a right triangle \( \triangle ABC \) with right angle at C, if \( \sin(A) = \frac{5}{13} \), find \( \cos(A) \) and \( \tan(A) \) without finding the angle \( A \) itself. (Hint: Use Pythagorean theorem to find the missing side).

2. A ladder leans against a wall, making an angle of \( 60^\circ \) with the ground. If the foot of the ladder is 4 meters from the wall, how high up the wall does the ladder reach? (Use trigonometric ratios of \( 60^\circ \)).

3. From the top of a cliff 50 meters high, the angle of depression to a boat at sea is \( 30^\circ \). How far is the boat from the base of the cliff? (Angle of depression is the angle below the horizontal).

4. Explain why, for any acute angle \( \theta \), \( \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} \). Show this relationship using the definitions of sine, cosine, and tangent in terms of opposite, adjacent, and hypotenuse.

5. (Conceptual) As the angle \( \theta \) in a right triangle increases from very close to \( 0^\circ \) towards \( 90^\circ \), how do the values of \( \sin(\theta) \), \( \cos(\theta) \), and \( \tan(\theta) \) change? Think about the ratios of sides as the angle changes.


6) Summary 🎉

  • Right Triangles: Triangles with one \( 90^\circ \) angle. Hypotenuse (opposite right angle), legs (opposite & adjacent to acute angles).
  • Trigonometric Ratios (SOH CAH TOA):
    • \( \sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}} \)
    • \( \cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}} \)
    • \( \tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}} \)
  • Reciprocal Ratios: Cosecant \( (\csc) \), Secant \( (\sec) \), Cotangent \( (\cot) \) are reciprocals of sine, cosine, tangent respectively.
  • Special Angles: Memorize \( \sin, \cos, \tan \) values for \( 30^\circ \), \( 45^\circ \), \( 60^\circ \). Use 30-60-90 and 45-45-90 triangle ratios.
  • Applications: Trigonometric ratios relate angles and side lengths in right triangles. Used to find unknown sides or angles.

Congratulations! You've now learned the fundamental trigonometric ratios in right triangles! These ratios are the bedrock for solving many trigonometry problems. Practice identifying opposite, adjacent, hypotenuse, and calculating sine, cosine, tangent for various right triangles. Mastering these ratios will unlock a wide range of applications in trigonometry and beyond! 📐🚀🌟

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